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integration of sin8x dx /(9+sin4x)1/2

plz explain in detail
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7 years ago

110 Points
```										take sin2x=tdt=2sinxcosxdx=sin2xdxnow the numerator of the expression: sin8xdx=2sin4xcos4xdx=4sin2xcos2xcos4xdx=4cos2xcos4xdt;now we know that cos2x=cos2x-sin2x=1-2sin2x=1-2tsimilarly, cos4x=1-sin22x=1-4sin2xcos2x=1-4t(1-t)=1-4t+4t2=4t2-2t-2t+1=(2t-1)2the denominator is (9+t2)1/2put the expressions in positionand expand the numeratoryou will get different powers of tseparate than integrate each part separatelyCoolDifficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE preparation.DO APPROVE IF THE ANSWER HELPS YOU.Now you can win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.Regards,Askiitians ExpertsRahul- IIT Roorkee
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7 years ago
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