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6 years ago


Answers : (3)


Dear margaret

1/x2 cos(1/x)dx

put 1/x  =t

      dx/x2 =-dt

intigral become


=sint + c

=sin(1/x) + c

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6 years ago

1. Solve the initial value problem:  dy/dx=1/√x+2,  y(2)=-1




6 years ago

∫1/x2 cos(1/x)dx put 1/x =t dx/x2 =-dt intigral become ∫ cos(t)dt =sint + c =sin(1/x) + c

6 years ago

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