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The strength of H2O2 (in g/litre) in 11.2 volume solution of H2O2 is?

The strength of H2O2 (in g/litre) in 11.2 volume solution of H2O2 is?

Grade:11

3 Answers

Umakant biswal
5349 Points
7 years ago
@rithesh 
volume strength is an outdated term referring to the volume of oxygen gas liberated from 1 volume of h2o2 solution . 
for example – if the volume strength is 20 volume , it means that 1 cm3 of h2o2 will produce from 20 cm3 of oxygen gas . 
acc to the equation 
2 moles of h2o2 = 22.4 L of oxygen at STP . 
so, by that first of all u have to calculate the MOLARITY of the solution . 
and use the formula 
moles of solute / volume of solution 
and the volume of solution is given as 11.2 
and u ned to calculate the no of moles . 
and use the formula 
mass/ molar mass , or given mass / molar mass 
and findout the no of moles , 
THE STRENGTH CAN BE CALCULATED BY THE FOLLOWING FORMULA 
11.2 * MOLARITY OF THE SOLUTION . 
from the prev formula , u find molaritty and apply it here , u will get the strength 
HOPE IT CLEARS YOUR DOUBT 
IF U NOT ABLE TO FIND THE ANSWER , THEN LET ME KNOW 
GOOD LUCK ..
Jaishree
15 Points
5 years ago

10 volume solution of H2O2 means that 1L of this H2O2 will give 10 L of oxygen at STP 

2H2 O2 ( l) → O2( g) +2 H2O( l) 

2×34 g       22.4 L at STP 

22.4 L of O2 at STP is produced from H2O2 = 68 g 

20 L of O2 at STP is produced from H2O2=68X20/22.4 = 60.72 g

Therefore, strength of H2O2 in 20 volume H2O2 = 60.72 g/L

Rishi Sharma
askIITians Faculty 646 Points
3 years ago
Hii Rithesh,
The solution of the problem is as follows
11.2 volume solution of H2O2means that 1L of this H2O2will give 11.2 L of oxygen at STP
2 H2O2( l) → O2( g) +2 H2O( l)
2×34 g 22.4 L at STP
22.4 L of O2at STP is produced from H2O2= 68 g
11.2 L of O2at STP is produced from H2O2=68X11.2/22.4 = 34 g
Therefore, strength of H2O2in 11.2 volume H2O2= 34 g/L
Thanks
I hope above solution will clear your all doubts.
Please feel free to post and ask as much doubts as possible.
All the best.

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