The enthalpy change involved in the oxidation of glucose is -2880 KJ mol-1. 25% of this energy is available for muscular work. If 100 KJ of muscular work is needed to walk one kilometre, what is the maximum distance that a person will be able to walk after consuming 120 gm of glucose??

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Arun · Answer

−mgh= 100 25 ​ ×n(−2808KJ) −6.25×9.8×3= 100 25 ​ ×n(−2808KJ) −183.75J= 100 25 ​ ×n(−2808×10 3 J) n= 25×(−2808)(1000) −183.75×100 ​ ⇒ 25×28080 183.75 ​ ⇒0.00026moles. massofglucose=n×molarmass ⇒0.00026×180.156⇒0.0468g. ​

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The enthalpy change involved in the oxidation of glucose is -2880 KJ mol-1. 25% of this energy is available for muscular work. If 100 KJ of muscular work is needed to walk one kilometre, what is the maximum distance that a person will be able to walk after consuming 120 gm of glucose??

The enthalpy change involved in the oxidation of glucose is -2880 KJ mol-1. 25% of this energy is available for muscular work. If 100 KJ of muscular work is needed to walk one kilometre, what is the maximum distance that a person will be able to walk after consuming 120 gm of glucose??

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The enthalpy change involved in the oxidation of glucose is -2880 KJ mol-1. 25% of this energy is available for muscular work. If 100 KJ of muscular work is needed to walk one kilometre, what is the maximum distance that a person will be able to walk after consuming 120 gm of glucose??

The enthalpy change involved in the oxidation of glucose is -2880 KJ mol-1. 25% of this energy is available for muscular work. If 100 KJ of muscular work is needed to walk one kilometre, what is the maximum distance that a person will be able to walk after consuming 120 gm of glucose??

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