Compound A is [Cr(NH 3 ) 4 ClBr]Cl Comound B is [Cr(NH 3 ) 4 Cl 2 ]Br Question is attached with the image! [ALTSM 01/03 Q90] Pls show how you calculated EAN.

Question

nipun jain · Answer

EAN=24-3+2*6=33 ATOMIC NO.---24 OXIDATION STATE---3 COORDINATION NO.---6 FOR BOTH THE EAN VALUE WILL BE SAME

nipun jain · Answer

ans is option 1

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Compound A is [Cr(NH 3 ) 4 ClBr]Cl Comound B is [Cr(NH 3 ) 4 Cl 2 ]Br Question is attached with the image! [ALTSM 01/03 Q90] Pls show how you calculated EAN.

Compound A is [Cr(NH₃)₄ClBr]Cl
Comound B is [Cr(NH₃)₄Cl₂]Br

Question is attached with the image!
[ALTSM 01/03 Q90]

Pls show how you calculated EAN.

2 Answers

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Compound A is [Cr(NH 3 ) 4 ClBr]Cl Comound B is [Cr(NH 3 ) 4 Cl 2 ]Br Question is attached with the image! [ALTSM 01/03 Q90] Pls show how you calculated EAN.

Compound A is [Cr(NH3)4ClBr]ClComound B is [Cr(NH3)4Cl2]Br Question is attached with the image![ALTSM 01/03 Q90] Pls show how you calculated EAN.

2 Answers

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Compound A is [Cr(NH₃)₄ClBr]Cl
Comound B is [Cr(NH₃)₄Cl₂]Br

Question is attached with the image!
[ALTSM 01/03 Q90]

Pls show how you calculated EAN.