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Co(NH3)6-dimagnetic but [Co(F6)]is paramagnetic why

Co(NH3)6-dimagnetic but [Co(F6)]is paramagnetic why

Grade:12th pass

4 Answers

Shramana Kar
112 Points
6 years ago
In both compound Co^3+(3d6) ion is present. But NH3 is a strong field ligand. So in 1st compound 6 electrons of 3d orbital pair and 2 d orbital becomes empty and the hybridization is d2sp3, inner orbital complex. As there is no unpaired electron the compound is diamagnetic. In 2nd compound F^- is a weak field ligand. So 3d electrons do not pair. Here the hybridization is sp3d2, outer orbital complex. So there are 4 unpaired electrons in 3d orbital & it is paramagnetic.Please approve my answer if you find it helpful...
abhishek mishra
51 Points
6 years ago
All octahedral comlexes of Co+3 are low spin, diamagnetic except [CoF6]3- and [Co(H2O)3F3], and it cant be explained by VBT.
if you use concept of weak field and strong field then how will you explain that [Co(OX)3]3- is diamagnetic whether oxalate is a weak field ligand.
Onkar Susladkar
35 Points
6 years ago
Because NH3 is strong field legand and F is week field legand that`s way NH3 can push the electron in the inner shell of the central metal atom as this also due to the NH3 can form inner orbital complex
ankit singh
askIITians Faculty 614 Points
3 years ago
As you can see, the 4 unpaired electrons remain as it is and give [CoF6]3- a 'PARAMAGNETIC' nature. ... As you can see due to pairing up NO unpaired electrons remain in the d-orbitals, and hence [Co(NH3)6]3+ is 'DIAMAGNETIC'

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