a photon of 300nm is absorbed by a gas and then re emitts two photons.one reemitted photon has a wavelength of 500nm.calculate energy of other photon

Question

Umakant biswal · Answer

@ roohinaya
i am giving you the correct approach to solve this question .
energy absorbed for photon = hc / lambda (1 ) = hc / 300 * 10 ^ -9
energy reemitted out for phtoton = hc / lambda (2) = hc / 500 * 10 ^-9
energy absorbed = energy for emitted photon = energy for 2^nd emitted photon
energy for 2^nd emitted photon = hc / 500 * 10 ^ -9
now put the value of h as planks constant and c as the speed of light ,
then u will get the answer .
HOPE IT CLEARS YOUR DOUBT
ALL THE BEST ..

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a photon of 300nm is absorbed by a gas and then re emitts two photons.one reemitted photon has a wavelength of 500nm.calculate energy of other photon

a photon of 300nm is absorbed by a gas and then re emitts two photons.one reemitted photon has a wavelength of 500nm.calculate energy of other photon

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a photon of 300nm is absorbed by a gas and then re emitts two photons.one reemitted photon has a wavelength of 500nm.calculate energy of other photon

a photon of 300nm is absorbed by a gas and then re emitts two photons.one reemitted photon has a wavelength of 500nm.calculate energy of other photon

1 Answers

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