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If the electronegativity difference between two atoms A and B is 2.0, then the percentage distribution character in the molecule is (A) 54%(B) 46%(C) 23%(D) 72%
The percentage ionic character is related to electronegativity difference between the two atoms. It is given by Hannay and Smith relationship.
%age ionic character.
= 16 (XA − XB) + 3.5 (XA − XB)2
Here, XA and XB are elecrtronegativities of two atoms A and B
\ % ionic character = 16(2) + 3.5(2)2 = 46%
or covalent character = 100 – 46 = 54%
b
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