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volume of air required to oxidise 210ml sulphur dioxide to sulphur trioxide , if air has 21% oxygen
volume of air required to oxidise 210ml sulphur dioxide to sulphur trioxide , if air has 21% oxygen=
2SO2 + O2 -------> 2SO3
210 gm 0.21 ''a'' gm
210/(64 x 2) = 0.21a/(32 x 1)
AfTER solving x comes = 250 ml.
Thus it volume of air required to oxidise 210ml sulphur dioxide is 250 ml.
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