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```				   calculate de-Broglie wavelength of an electron travelling at 1% of the speed of light.
a) 2.73 x 10-24
b) 2.42 x 10-10
c) 242.2 x 1010
d) none of these

plz solve and explain the solution.....
```

6 years ago

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```

λ = h/mc
In your problem, velocity = c/100 ( since the velocity is 1 %)
Sub c=c/100 in above equation, You will get λ = 100 h/mc
Sub values of h,m and c. Arrange the powers of 10. The answer will be 2.42 x 10-10.
So, Your answer will be (b) 2042 x 10-10.  Hope you understand. Do well.
```
6 years ago
```										(lamda) = h/mv              (h is planks constant , h = 6.6*10-34 & m is mass of particle)
v = 1% of speed of light = C/100                 (C is speed of light & C=3*108)
lamda = h/mv
=100h/mC                                 (m = 9.1*10-31kg , mass of electron)

= 0.241*10-9 m
=0.241nm      or 2.41(angstorm)

```
6 years ago

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