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Amit Tapas Grade: 10
        

If the weight of 5.6 lit of of a gas is 11g at stp.The gas is


1. SO2


2. NO


3. N2O

6 years ago

Answers : (2)

AKASH GOYAL AskiitiansExpert-IITD
419 Points
										

Dear Amit


wt of 22.4 lit gas=(22.4/5.6)*11=44g


wt of N2O = 14*2+16=44g


All the best.


AKASH GOYAL


AskiitiansExpert-IITD


 


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6 years ago
vikas askiitian expert
510 Points
										

22.4L of gas = 1mol


1L= 1/22.4 mol


5.6L = 1/4 mol


let molar mass of gas is M then


5.6L = M/4gm =11gm  (given)


    so M=11*4=44gm


so the gas is N2O

6 years ago
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