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 to determine the hybridisation from pie bonds or sigma bonds

2.what is a triatomic molecule?

3.why does phosphine have lower melting point than ammonia?

4.although i3- is konown ,f3- is not why?

nacl gives a white precipitate with agno3 but ccl4 or chcl3 does not...plzzz explain!!

i would be really thankfull if you wud clear my doubts asap!

6 years ago


Answers : (1)


Hii nishad ..


Hybridisation is actually not only determined by sigma and pie bonds..there are many defination to find out hybridisation of compound ...well i will tell you with example


Electron               Hybridisation


2                                 sp

3                                sp2

4                                sp3

5                                sp3d

6                                sp3d3


NH3                          H  --N(--H) -- H   so here we have three sigma bond...and one lone pair on N   so 3 + 1 = 4

so hybridisation = sp3


PCl5   here phoshphorus has 5 electron in outer most shell..5 Cl combines with all and form 5 sigma bond ..

so gives  sp3d .


NO2+    N + has outer most e- = 4  two oxygen combines with four electron making two double bond ..


So we have total bond = 4   hence hybridisation sp3



2) I3-  is term as triatomic...with three I atoms combined each other two form a compund

3) Amonia exibits hydrogen Bonding ....

4) Because size of F is very small as compared to I ....thats why triatomic and negative charge leads to a larger repulsion in case of F ....hence F3- is not possible



In case CCl4 ...Cl is in stable state and there is no chance that bond will break between C and no chance of formation of AGcl when mixed with AgNO3


In case ChCl3...instead of Cl  ...Bond of C-H breaks out due to stability of C-cl3 (resonace)..which leads  no precipitation of AgCl ...


In case of breaks in Na+ and Cl-  and finally Cl- combines with AgNo3...and precipitate of AgCl is formed


I hope i have explained it





6 years ago

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