the smaller the size of the cation and larger the size of the anion, greater the covelent charater of an ionic bond.


why, explain me please.

4 years ago

Share

Answers : (2)

                                        

DEAR Ravi ,


In case of ions , we associate polarising power of cation and polarisability of anion , which are the power of cation to distort the anions electronic cloud and power of anion to get distorted . The whole process is like that of electrical induction. the cation pulls the electronic cloud of anion to itself so that the elctron pair on anion is shared between two as in the covalent bond. Now greater the charge density on cation greater is its polarising power and correspondingly for anion. so bond become more and more covalent with smaller size of action and larger size of anion.



 GOOD LUCK !!!!


Please feel free to post as many doubts on our discussion forum as you can. We are all IITians and here to help you in your IIT JEE preparation.


Now you can win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.

4 years ago
                                        

Due to greater concentration of positive charge on a small area, the smaller size of cation has high polarising power, so greater the ionic character of an ionic bond. While larger size of the anion, the greater is its polarisability. It is due to the fact that the outer electrones of a large anion are losely held and hence can be more easily pulled out by the cation.and greater the ionic character of an ionic bond.

4 years ago

Post Your Answer

More Questions On Inorganic Chemistry

Ask Experts

Have any Question? Ask Experts
Post Question
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!!
Click Here for details
HOW DO YOU calculate the equivalent mass of KMnO 4 in acidic medium?
 
 
KMnO4 has a Molar mass of 158.04 g/mol There are two possibillities: 1. KMnO4 as an oxidizer in acidic media: MnO4- + 8 H+ + 5e- --> Mn2+ + 4H2O (gained 5 electrons from reductant) I.e....
  img
Suraj Prasad 4 months ago
why there is ahydride gap in 7 th 8 th and 9 th groups of d block
 
 
Hydrogen combine with many element forming hydride in which its oxidation state is -1. The 7th8thand 9thgroup of d and f block donot form any hydrides with hydrogen because these elememt...
  img
Sunil Kumar FP 5 months ago
The ratio of difference int he wavelengths of 1 st and 2 nd lines of lyman seres in H-like atim of difference in wavelength for 2 nd and 3 rd lines of same series is - 2.5:1 3.5:1 4,5:1...
 
 
1/λ = 1.097 x 10^7 ( 1 - 1/n^2) n=2 => 1/λ = 1.097 x 10^7(1 - 1/4) = 0.82275 x 10^7 per m => λ = 1.215 x 10^(-7) m ------------eq(1) n=3 => 1/λ = 1.097 x...
  img
Sunil Kumar FP 5 months ago
if the solubility product of BaSO 4 is 1.5*10 -10 in water. It’s solubility , in moles per litre is
 
 
BaSO4 ionises to give – BaSO4 Ba 2+ + SO 4 2-- Suppose solubility of BaSO4 is s mol/l.It would give s mol/l of Ba2+ ions and s mol/l of SO4 2- ions on dissociation. Now, solubility...
  img
Aarti Gupta 3 months ago
 
BaSO4<............>Ba+..+..SO4- C........................0...........0.......(intially) C-s.....................s..............s........(at equilibrium) where s is the...
  img
Naveen Kumar 3 months ago
 
If solubility product is 1.5*10^10,then for given reaction relation between solubility product and solubility is s.product=4*S^3 , where ‘S’ is solubility in mol/lit.the above relation comes...
 
aishwaryawagh 6 days ago
find n factor of h2so4 in(yes it is unbalanced equation is it necessary to make it balance?) pbo2+pb+h2so4=pbso4+h2o
 
 
yes true............. If alternatively we can see that for 2 moles of h2so4, one mole of pb is changing from 0 to +2 so for 1 h2so4, +1 is the change and so is the n-factor. Thanks for your...
  img
Naveen Kumar 2 months ago
 
First of all you need to understand about the balencing equation. Without balencing it you should not proceed further. FOR CALCULATING n-FACTOR, WE SHOULD HAVE CHANGE IN OXIDATION STATE PER...
  img
Naveen Kumar 2 months ago
 
The ionic reactions of the given reaction are PbO 2 + SO 4 -2 + 4H + + 2e - = PbSO 4 + 2H 2 O Pb + SO 4 2- = PbSO 4 + 2e therefore the net reaction becomes Pb + PbO 2 + 2 h 2 SO 4 = 2PbSO 4...
 
Himaja 2 months ago
Molarity of 30 volume H2O2 is. 1- same as its normality 2-half as its normality 3- doble as its normality 4-onefourth as its normality
 
 
As we know that Normality = Molarity X n-factor N= M X n-factor For H2O2, n-factor = 2 (No of replaceable hydrogens) N= M X 2 So option (2) is correct....
  img
Ramreddy 2 months ago
 
thanku sir
 
Shriya Mehrotra 2 months ago
View all Questions »