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				   haemoglobin contains 0.25% iron by mass.the molar mass of haemoglobin is 89600.the number of iron atoms present in 1 mole of haemoglobin is?

requires the explaination of the chapter.

6 years ago


Answers : (1)


Hi Sanskriti,

Your solution is as follows:

0.25 % by mass means:

0.25 gms of iron in 100 gms haemoglobin.

therefore in 89600 gms i.e. 1 mole of haemoglobin contains:  0.25 x 89600 = 896 x 0.25 = 224 gms of fe


But 1mole of Fe i.e. 56 gms comtains 6.023 x 1023 ( Avogadro number. NA) atoms.

therefore 224 gms of Fe will contain:  224 x 6.023 x 1023  = 2.409 x 1024 atoms.




With Regards,


6 years ago

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