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in the complex with formula Mcl3.4H2O, the coordination number of the metal M is six and there is no molecule of hydration in it . the volume of 0.1 M AgNo3 solution needed to precipitate the free chloride ions in 200ml of 0.01 M solution of the complex is ?
Dear Piyush,
According to question=
Coordination no. of metal is six
Hence formula of compound = [M(H2O)5Cl] Cl
Meq. Of AgNo3 = Meq. Of free chloride in complex
.1 × v = 200 × .01
V = 200 × .01/.1
= 20 ml.
With Regards,
Abhishek Jain
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