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`        a line x=k intersects graph of y=log5x and the graph of  y=log5(x+4) .the distance b/w points of intersection is    0.5      , given k=a+(b)1/2..where a & b are integers..the value of    a+b  is...........`
7 years ago

147 Points
```										Dear rahul
given distance b/w points of intersection is    0.5
ie  log5(k+4) -log5(k)  =1/2
or log5(k+4)/k  =1/2
or (k+4)/k  =√5
k=4/(√5 -1)
=√5 +1
so  a=1   and b=5
a+b=6
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7 years ago
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