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CORRECT ORDER OF STABILITY IS
1. -2CH-C(TRIPLE BOND) CH & 2. -CH=C=CH-
a. 1>2 b. 2>1 c. 1=2 d. none of these
Dear Rahul,
The correct answer to this question would be (b).
As you can see, both (1) & (2) are the different resonance structures of the same compound. But in (2) the charge is more delocalised. Greater delocalisation of charges results in greater stability. Therefore (2) will be more stable than (1).Let me know if you've further doubts regarding this.All the best !!!Regards,Askiitians ExpertsHimanshu Geed
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