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The coefficient of three consecutive terms in the expansion of (1+a) n are in the ratio 1:7:42 then find n value.

The coefficient  of three consecutive terms in the expansion of (1+a)n are in the ratio 1:7:42 then find n value.

Grade:12th Pass

6 Answers

L GOUSE BASHA
316 Points
8 years ago
 
The coefficient  of three consecutive terms in the expansion of (1+a)n are in the ratio 1:7:42 then find n value.
SHANMUKESHWAR
461 Points
8 years ago
The coefficient  of three consecutive terms in the expansion of (1+a)n are in the ratio 1:7:42 then find n value.
Gavvala Ganesh
551 Points
8 years ago
The coefficient  of three consecutive terms in the expansion of (1+a)n are in the ratio 1:7:42 then find n value.
Gowri sankar
292 Points
8 years ago
MR PRAPUL,
               The coefficient  of three consecutive terms in the expansion of (1+a)n are in the ratio 1:7:42 then find n value.
T.kumar
281 Points
8 years ago
of three consecutive terms in the expansion of(1+x)n are in the ratio 1:7:42. find n. ... or, x = 1. putting value of x in 1st equation , n = 7. Hence n = 7. tHuMpS uP ...
Prabhakar ch
577 Points
8 years ago
The coefficient  of three consecutive terms in the expansion of (1+a)n are in the ratio 1:7:42 then find n value.
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