A real value function f ( x ) satisfied the functional equation f ( x-y ) = f ( x ) f ( y ) - f ( a-x ) f ( a + y ) and f ( 0 ) = 1, f ( 2a-x ) =?

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Riddhish Bhalodia · Answer

Put x=y=0 and then we get f(a) = 0 now put x=a then f(a-y) = f(a)f(y) &ndash; f(0)f(a+y) = -f(a+y) now put y = x-a then f(2a-x) = -f(x)

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A real value function f ( x ) satisfied the functional equation f ( x-y ) = f ( x ) f ( y ) - f ( a-x ) f ( a + y ) and f ( 0 ) = 1, f ( 2a-x ) =?

A real value function f ( x ) satisfied the functional equation f ( x-y ) = f ( x ) f ( y ) - f ( a-x ) f ( a + y ) and f ( 0 ) = 1, f ( 2a-x ) =?

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A real value function f ( x ) satisfied the functional equation f ( x-y ) = f ( x ) f ( y ) - f ( a-x ) f ( a + y ) and f ( 0 ) = 1, f ( 2a-x ) =?

A real value function f ( x ) satisfied the functional equation f ( x-y ) = f ( x ) f ( y ) - f ( a-x ) f ( a + y ) and f ( 0 ) = 1, f ( 2a-x ) =?

1 Answers

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