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A ball is thrown vertically upward with a velocity of 30 metre per second if the acceleration due to gravity is a gas metre per second square what will be the distance travelled by it in the last second of motion before again come to his hand

A ball is thrown vertically upward with a velocity of 30 metre per second if the acceleration due to gravity is a gas metre per second square what will be the distance travelled by it in the last second of motion before again come to his hand

Grade:12th pass

1 Answers

Arun
25750 Points
3 years ago
Upward velocity given to the ball is v.
Acceleration due to gravity g acts on it in downward direction.
Distance covered by it in T seconds, S 
T
​ 
 =vT− 
2
1
​ 
 gT 
2
  
Distance covered by it in T−1 seconds, S 
T−1
​ 
 =v(T−1)− 
2
1
​ 
 g(T−1) 
2
  
Hence distance covered in last second, S=S 
T
​ 
 −S 
T−1
​ 
 
∴ S=[vT− 
2
1
​ 
 gT 
2
 ]−[v(T−1)− 
2
1
​ 
 g(T−1) 
2
 ]
OR S=[vT− 
2
1
​ 
 gT 
2
 ]−[vT−v− 
2
1
​ 
 g(T 
2
 +1−2T)]
⟹ S=v+ 
2
1
​ 
 g(1−2T)

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