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60ml of a mixture of Nitrous oxide and nitric oxide was exploded with excess of hydrogen. If 38 ml of N2was formed , calculate the volume of each gas in the mixture.

60ml of a mixture of Nitrous oxide and nitric oxide was exploded with excess of hydrogen. If 38 ml of N2was formed , calculate the volume of each gas in the mixture.

Grade:12th pass

2 Answers

vaibhav
15 Points
4 years ago
let x be the volume of NO 
the reaction takes as 
2NO +2H2 ----> N2 +2H2O
2x                    x
N2O +H2 ----->N2 +H2O
60-2x              60-2x
the volume of notrogen collected is 38
therefore   60-2x+x=38
                x=44
hence volume of NO and N2O are 44 and 16 respectively
Vikas TU
14149 Points
4 years ago
Dear student 
If we take the volume of the mixture to be 2x ml of NO. Then we get that the  volume of N2O will be present = (60−2x) ml.
We can write the balanced chemical equations as such:
Equation-               2NO + 2H2 -> N2+2H2O  .
Number of moles -   2x                    x.
Equation-                N2O + H2→ N2+H2O.
Number of moles-  60−2x         60−2x.
Thus from the quetion we get to know that the volume of N2 collected is 38 ml.
Hence, we can write that 60−2x+x=38 or x=22 ml.
Therefore, the volumes of NO and N2O which are present in the mixture will be:
The volume of NO will be=2x=2×22=44 ml.
The volume of N2O will be=60−44−16 m.
Regards  

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