What was the total marks of JEE-2010?You would rate the difficulty level as,what?
                   

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Sir, -How rank is decided in jee advanced? -Is it decided only on marks that we get in jee advanced paper?
 
 
It’s decided solely on the basis of the marks you secure on the JEE Advanced paper. Thanks & Regards Aziz Alam IIT Roorkee askIITians
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Aziz Alam one month ago
A body is thrown horizontally with a vel. u from top of the tower. The displacement of the stone when the horizontal and vertical vel. are equal?(Horizontal projectile)
 
 
Hello Dear student, v= gt u=gt t=u/g the horizontal displacment = u*u/g the vertical displacment, s= .5g (u/g)^2
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Sher Mohammad one month ago
sir, i got ee in iit patna.. and unluckily expecting a rank of around 30000 in mains. and therefore will get nit durgapur it. what should be my choice??? btw i am also getting ee in jadavpur...
 
 
If you have EE in IIT Patna and your possible options include NIT Durgapur and EE in Jadavpur University, it’s better that you stick with EE in IIT Patna. And if you are thinking about...
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Aziz Alam one month ago
Rank these for CSE on future prospects,please? NITT,NITW,NITK,NITA,COEP?
 
 
Ranking of CSE in the mentioned colleges on the basis of college rankings, since CSE is top branch in all these NITs. the priority order can be decided on the basis of college ranking: 1....
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Ramreddy 28 days ago
An ant is at the vertex of cube of side 'A' .It is moving with constant speed 'U'.The minimum time taken by ant to cover the maximum displacement with in the cube is-
 
 
Dear rahul minimum time take by ant when it moves in straight line along AB minimum distance = √(2a) 2 +a 2 =a√5 so time taken =a√5/U Please feel free to post as many...
 
Badiuddin askIITians.ismu Expert 4 years ago
sir i will join in a btech this year. can i possibly give kvpy 2014
 
 
Hi, Yes, you can give KVPY this year as well. You eligible under SB Stream. For detailed information on KVPY, refer this link : kvpy.org.in/main/eligibility.htm
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Yash Baheti 29 days ago
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