in a triangle (a-b)/(b-c)=(s-a)/(s-c),,then what will be the ratio of r1,r2,r3??

4 years ago


Answers : (1)


Dear dolly



1/(s-a)(b-c)  = 1/(s-c)(a-b)

Δ/(s-a)(b-c)  = Δ/(s-c)(a-b)

r1/(b-c)  = r3/(a-b)  .................1


now  we know   (b-c)/r1   + (c-a)/r2   + (a-b)/r3  =0

    so from equation 1     2(b-c)/r1  = -(c-a)/r2

                                             r1/(b-c)  = -2r2/(c-a)

 so r1 : r2: r3  :: (b-c):(a-c)/2 : (a-b)

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4 years ago

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