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four different point on circle whose coordinate is (mi,1/mi) then which one is ture


a. m1*m2*m3*m4=1                b.1/m1*1/m2*1/m3*1/m4 =4

6 years ago

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Answers : (2)

										

Dear nishant


for simplicity let equation of circle is x2 +y2 =r2


put (m,1/m) point


so  (m)2 +(1/m)2 =r2


simplify it


  m4 -r2m2 +1=0


this equation has 4 roots m1,m2,m3,m4


product of all roots


 m1*m2*m3*m4=1





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Badiuddin

6 years ago
										Dear student Mr. Nishant


for simplicity let equation of circle is x2 +y2 =r2

put (m,1/m) point

so (m)2 +(1/m)2 =r2

simplify it

m4 -r2m2 +1=0

this equation has 4 roots m1,m2,m3,m4

product of all roots

m1*m2*m3*m4=1

Please feel free to post as many doubts on our discussion forum as you can.
If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly.
We are all IITians and here to help you in your IIT JEE & AIEEE preparation.

All the best.

Regards,
Askiitians Experts
Pramod Kumar, IITR Alumni
6 years ago

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