+91-87964 74404
FlagBACK
Question icon
IIT JEE Entrance Exam

230 JOULE WERE SPENT IN LIFTING A 10 KG WEIGHT TO A HEIGHT 2 m .CALCULATE THE ACCELERATION WITH WHICH IT WAS RAISED .TAKE g=10m/s2

Profile image of omkar ajnadkar
14 Years agoGrade
Answers icon

2 Answers

Profile image of nishad bagwe
14 Years ago

by conservation of energy,

the energy spent in doing the work=change in ke + change in pe

therefore, 230=10 x 2 x 2  + 0.5 x 10 x v2

230=40+5v2

v2=190/5

=38m/s

now,v2=2as

a=38/4

=9.5 m /s2

Profile image of Sahil
8 Years ago
According to mechanical energy conservation :- 230 = 1/2*10*v^2 + 10 * 10 * 2230-200= 5v^2v^2 = 2as6/2*2=a= 1.5m/s^2

Other Related Questions on iit jee entrance exam

question mark

Let S={x:x belongs to R(√3+√2)^(x^2-4) - (√3-√2)^(x^2-4)=10}. Then n(S) is equal to-

iit jee entrance exam
1 Answer Available

Last Activity: 10 Months ago

question mark
My rank is 29k, General, should I opt for any state college cse branch or some Nits in which in which I am getting ECE , chemical, mechanics etc....
 
iit jee entrance exam
1 Answer Available

Last Activity: 3 Years ago

question mark
How is Ranquer Eduzone,comparing, Akash,Fitjee,Resonance,Naryana
iit jee entrance exam
1 Answer Available

Last Activity: 4 Years ago

question mark
Can class 9th students study syllabus class  of 11th 
iit jee entrance exam
3 Answers Available

Last Activity: 4 Years ago

question mark
Sum of series 2[n/2] ! [n/2]!/ n! [2Co-2C2+3C2....+[-1]^n[n+1]2Cn] where n is an even positive integer. Kindly provide solution of this question and how to generalise this. How do we know that which expansion will give this?
iit jee entrance exam
1 Answer Available

Last Activity: 4 Years ago