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A straight line through the origin meets the parallel lines 4x+2y=9 and 2x+y+6=0 at P and Q respectively. Then the point O divides PQ in the ratio???

3 years ago

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Answers : (2)

                                        

Dear Pranavi,


y=kx,(2+k)x=-6,


x=-6/(k+2),y=-6k(k+2),this is Q


now P:(4+2k)x=9


x=9/(4+2k),y=9k/(4+2k)


OP=(9/(4+2k))√(1+k2)


OQ=-(6/(2+k))√(1+k2)


lOP/OQl=l-(9/6)*(k+2)/(2k+4)l=3/4


 


Please feel free to post as many doubts on our discussion forum as you can. If you find any question
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All the best Pranavi !!!


 



Regards,


Askiitians Experts


CHETAN MANDAYAM NAYAKAR

3 years ago
                                        

PO : OQ = 3:4


 2y = -4x + 9


2y = -4x - 12



The y-intercepts of these two lines are +9/2 and -12/2, respectively. The origin divides the segment as

9:12 = 3:4

3 years ago

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