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`        A straight line through the origin meets the parallel lines 4x+2y=9 and 2x+y+6=0 at P and Q respectively. Then the point O divides PQ in the ratio???`
6 years ago

Chetan Mandayam Nayakar
312 Points
```										Dear Pranavi,
y=kx,(2+k)x=-6,
x=-6/(k+2),y=-6k(k+2),this is Q
now P:(4+2k)x=9
x=9/(4+2k),y=9k/(4+2k)
OP=(9/(4+2k))√(1+k2)
OQ=-(6/(2+k))√(1+k2)
lOP/OQl=l-(9/6)*(k+2)/(2k+4)l=3/4

Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE preparation.
All the best Pranavi !!!

Regards,
CHETAN MANDAYAM NAYAKAR
```
6 years ago
anahita vn
32 Points
```										PO : OQ = 3:4
2y = -4x + 9
2y = -4x - 12
The y-intercepts of these two lines are +9/2 and -12/2, respectively. The origin divides the segment as9:12 = 3:4
```
6 years ago
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