what is my rank going to be for 229 marks according to new key please tell me if can get cs/eee/mech. at iit hyderabad
Dear Aditya ,You have chances ..
Askiitians provide the IIT JEE cut off along with the opening and closing ran given below for IIT JEE cut off:
http://www.askiitians.com/iit-jee-2011-counselling.html
Click for opening and closing ranks: http://www.askiitians.com/iits-2009-2010-opening-and-closing-rank.aspx
Thanks and All the Best ..
Let S={x:x belongs to R(√3+√2)^(x^2-4) - (√3-√2)^(x^2-4)=10}. Then n(S) is equal to-
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