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what constant force p is required to bring a 50kg body which starts from rest to a speed of 10m/s in 7m neglect friction
 
 
a=v 2 /2s =>a=100/14=7.14 m/s 2 F=ma=50*7.14=357.14 N...
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Aziz Alam 3 months ago
 
use v 2 -u 2 =2*a*s given u=0 and s= 7 m and v=10 m/s 100= 2*a*7 a= 100/14 Force required(p)= ma = 50*100/14 = 357 N...
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Ramreddy 3 months ago
can I gave exam of JEE frome both city delhi and kanpur. it is possible?
 
 
2 attempts in a year are not permitted atleast by JEE. (I can expect the same for other exam conducting bodies too, certainly). So, NO...
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Ravi one month ago
 
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Aziz Alam one month ago
Find the locus of the mid point of the chord of a circle x 2 + y 2 = 4 such that the segment intercepted by the chord on the curve x 2 - 2x – 2y =0 subtends a right angle at the origin.
 
 
ohh , really?? have you even tried to draw the figure urself ??? all the segments intercepted on this curve inside the circle subtend an obtuse angle
 
abhidon3 one month ago
 
well its a correct question
 
Vikrant Prasad one month ago
 
hey man ,, why you guyz post such a question which are either wong or incompete ,, it wastes too much time ,,,
 
abhidon3 one month ago
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