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                   the gravitational force between a point like mass M and an infinitely long,thin rod of linear mass density d at a perpandicular distance L from M is ??
                   

4 years ago

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Answers : (2)

                                        

Dear Prachi


Gravitational field at a distance r from the infinitely long rod with liner mass density d = 2Gd/r


here r=L and force will be field x mass


force= 2GMd/L


 


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4 years ago
                                        

Gravitational Force is -Gm1m2 / r^2


since r is the radius and it is the prependicular distance between the rod and the point of mass M


the mass of the rod is d*V , since a rod is cylindrical the volume is pi*r*r*h and h = infinity


so mass of rod = d*infinity = infinity


Gravitational Force =  - G * infinity * M / L^2


                           =  -  infinity / l^2


since infinity divided by any positive number is also infinity


                           =  - infinity !


 


therefore gravitational force is - infinity


please approve if the answer is correct

4 years ago

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