number of values of 'a'(from 0 to 9) for which the no N = 2345631143a4 is divisible by 12 is:


0, 1, 2,more than 2


i know the ans is 2.. plz explain.thanks in advance


4 years ago

Share

Answers : (1)

                                        


Dear Jayati,


Solution:- For the number to be divisible by 12, it has to be divisible by 4 and 3.


Divisibility criteria for 3: Sum of the digits of the number should be divisible by 3.


Sum of the digits of N = a + 36


Since, 36 is divisible by 3. So, for N to be divisible by 3, 'a' can have following values- 0, 3, 6, or 9.


Now, Divisibility criteria for 4: The last 2 digits of the number should be divisible by 4. In our case, 'a4' should be divisible by 4.


'a4' can be 04, 34, 64, or 94. From these 4 values, only 4 and 64 are divisible by 4. Therefore, 'a' can be either 0 or 6.


ANS = 2


Please feel free to post as many doubts on our discussion forum as you can. If you find any question
Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE preparation.

All the best Jayati!!!

Regards,
Askiitians Experts
Priyansh Bajaj


4 years ago

Post Your Answer

More Questions On IIT JEE Entrance Exam

Ask Experts

Have any Question? Ask Experts
Post Question
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!!
Click Here for details
which is the best book of the pcm for the preparation of iit advance
 
 
I would like to give you the link of corresponding books, that would be hlpfull for IIT-JEE MAIN and Advanced...
  img
Saurabh Kumar 24 days ago
can I gave exam of JEE frome both city delhi and kanpur. it is possible?
 
 
2 attempts in a year are not permitted atleast by JEE. (I can expect the same for other exam conducting bodies too, certainly). So, NO...
  img
Ravi 25 days ago
 
  img
Aziz Alam 25 days ago
i have got a seat in iit roorkee and paid the fee in the frst round of seat allocation. i have to inform to iit roorkee for my admission. but due to some reasons i cannot go to roorkee. the...
 
 
JEE office in Roorkee Contact No. +91-1332-285224, 284272 U.G. Admission Contact No. +91-1332-284289, 285200 Registrar IIT Roorkee Contact No. +91-1332-285311 The above are the means by...
  img
Aziz Alam 4 months ago
 
i tried to contact them but the phones sometimes were busy and sometimes it doesn’t connect. can i try a letter to the chairman of jee advanced for refund. they have specified they wont give...
 
ranganath 4 months ago
I am a class 10th student of D.P.S Ranchi.I would like to know which among the is better for me.I am a good student getting always around 94-95% marks.Please help me!
 
 
dth:95%;"> well if u r so good then u sud go wid fiitjee or even vidyamandir as they have a high level which is required to crack iitjee
 
jaskrit kohli singh 4 years ago
sir, how is CSE at NIT-SIKKIM??
 
 
It is well konown fact that almost all NITs are having good infrastructure,facilities but however placements depends strongly on the location in which it is situated.But CSE is a top branch...
  img
Ramreddy 4 months ago
sir how to find dissociation in chemical eq? 2 if temperature does not change in a rection does it mean that there is no reaction
 
 
Dissociation in chemistry and biochemistry is a general process in which molecules (or ionic compounds such as salts, or complexes) separate or split into smaller particles such as atoms,...
  img
Suraj Prasad 2 months ago
View all Questions »