number of values of 'a'(from 0 to 9) for which the no N = 2345631143a4 is divisible by 12 is:


0, 1, 2,more than 2


i know the ans is 2.. plz explain.thanks in advance


4 years ago

Share

Answers : (1)

                                        


Dear Jayati,


Solution:- For the number to be divisible by 12, it has to be divisible by 4 and 3.


Divisibility criteria for 3: Sum of the digits of the number should be divisible by 3.


Sum of the digits of N = a + 36


Since, 36 is divisible by 3. So, for N to be divisible by 3, 'a' can have following values- 0, 3, 6, or 9.


Now, Divisibility criteria for 4: The last 2 digits of the number should be divisible by 4. In our case, 'a4' should be divisible by 4.


'a4' can be 04, 34, 64, or 94. From these 4 values, only 4 and 64 are divisible by 4. Therefore, 'a' can be either 0 or 6.


ANS = 2


Please feel free to post as many doubts on our discussion forum as you can. If you find any question
Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE preparation.

All the best Jayati!!!

Regards,
Askiitians Experts
Priyansh Bajaj


4 years ago

Post Your Answer

More Questions On IIT JEE Entrance Exam

Ask Experts

Have any Question? Ask Experts
Post Question
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!!
Click Here for details
|z|
 
Hello Sir..!! my friend is very intelligent. but her capacity to score is 920/1000 in AP .How much should she score in JEE examz to get into IIT??
 
 
she should focus in getting atleast 200+ marks in JEE mains....
  img
Amit Shekhar 2 months ago
 
200+ marks...
  img
Amit Shekhar 2 months ago
i don,t have much time now for iit jee. my preparation seems to be ok ok.please tell me the scoring chapters, on which i have to focus more.
 
 
If you have finished all the chapters and revise all these several times with practising good problems and also try to solve previous 20 years questions asked in IIT-JEE exam. You would...
  img
Naveen Kumar one month ago
if a+b+c+d=0 then(a+d)^2+(b+d)^2+(c+d)^2 is equal to
 
 
Opening the bracket terms and seperating the square terms and terms with d would give a^2+b^2+c^2+3d^2+2d(a+b+c) But, a+b+c= -d So, a^2+b^2+c^2+3d^2+2d(-d) and solve ahead to get the...
  img
Ravi one month ago
sir Is all india overall rank or all india category rank considered for jee main 2014 counselling?
 
 
For admission into home state colleges HOME STATE rank is considered. For all other colleges mostly it is All India category rank is considered first and then AIR overall is considered.
  img
Ramreddy 4 months ago
hello Sir, I am a B.Tech student from cse steam and I have selected in a good multinational company and I am willing to write GATE 2010.Most of my friends suggested me to opt for the job as...
 
 
If you are from IIT then there is not write any gate exam and M Tech will not be a good choice. because after M Tech fron any IIT , the salary difference will be 5 to 8K@month only. and that...
 
AskiitianExpert Pramod-IIT-R 4 years ago
Sir, I have secured 2251 rank in JEE Advanced, under SC Merit list. What are the chances of getting an IIT in the second list? And is it possible to get a seat in IIT Delhi? And if not IIT...
 
 
Hi, For a better estimate, visit our college and branch predictor at askiitians.com You can also see the last years opening and cloasing rank. For admission in NIT Delhi, you need rank in...
  img
Yash Baheti 2 months ago
View all Questions »