let agiven line L1 intersect the x and y axis at P &Q respectively.Let another line L2 perpendicular L1 cut the x and y axis at R & S respectively.Show that the locus of the point of intersection of the lines PS & QR is a circle passing through the origin.

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Answers : (1)

                                        

let given line is L1: y=mx+c


(P,Q)=(-c/m,0) , (0,c)


now L2 is perpendicular to line L1


slope of L2*slope of L1=-1            (m1m2=-1)


 eq of L2: y=-x/m + k                 (k is any variable)


(Q,R)=(km,0),(0,k)


eq of PS is y=mkx/c + k and.................1


eq of QR is  y=-x/km + c ...................2


let the point if intersection be (X,Y)


 after solving 1 and 2


X= (c-k)/(mk/c + 1/mk )...............3


Y= (km+1/m) /(mk/c + 1/mk)...........4


 eliminate k by solving eq 3 and 4 you will get the equation in terms of X,Y and c .......this will give the required locus which is circle passing through origin...

4 years ago

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