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                   the four digit no. 2652 is such that any two consecutive digits from it make a multipleof 13. another no. n has this same property, is 100 digits long and begins in a 9. the last digit of n is ? pls explain how this type of Qu are solved ? 

5 years ago


Answers : (1)


such questions are solved by pure logic.

there is no set formula for them


which digit should come after 9



and after 1


after 3?


after 9?


so the series continues

the number is

9139139139.........upto hundred digits.

the 99th digit would 3

and hundredth? well it should be 9 right??



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