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a glass(n=2) coverd by two spherical surfaces(each ROC=10) situated in air.an object is situated 10 cm from glass.find the final image after bi-refraction from spherical surfaces
let v be distance of first image from first surface. 1/10 +2/v =(2-1)/10 therefore v=∞,for second surface u=-∞,
therefore 2/(-∞) + 1/v =(1-2)/(-10) thus v=10cm. therefore the final image is 10cm from the glass on the opposite side of the glass as the object
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