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Hi,


Unexpected result of JEE 2010, as all of us are aware that, there were blunders in JEE paper 2010 and to those students who were appearing 2nd time, it came as a nightmare, as per my views



1.    The results of JEE 2010 should NOT be dissolved.
2.    But, the students who have appeared 2nd time should be allowed a 3rd attempt as exception
3.    This would be the real justice to all those students who could not make it to IITs second time due to irresponsible behavior of JEE.

In case you support my cause, please try to bring this thing to Media / Hon'ble HRD Minister Mr. Kapil Sibal.

Regards,
Vivek
E Mail : vivek.ambashtha@gmail.com

5 years ago

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Answers : (1)

										

This is my second attempt and i managed a rank of 6631{was xpectin abt 3000}.Many of my friends who were expectin abt 250-260 got in 6000s and those expecting 290-300 got a rank of 1300 or 1500.And sum expecting close to 200 didnt even qualify{all of them gave a second attempt},


But we cant drop another year.Its all FATE

5 years ago

Post Your Answer

i got 83% cbse want doing drop should go for improvement
 
 
Not required. But If you have scored very well in jee advanced or have the complete confidance then you can go for it. Thanks.
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Vijay Mukati 9 months ago
 
I am not in favour of dropping a year, one must do so only when one is dead sure to imrove the next time....follow these guidelines if you have made up your mind to drop and prepare –Stay...
 
Ayushmaan Vardhan 9 months ago
 
There is a wide range of insrtitutions where you may get admission, and almost every college/university today claims to provide quality education using ultra-modern methods of technology for...
 
Mohit Kumar 2 months ago
Is the official syllabus provided for jee advanced, sufficient for cracking advanced or some more knowledge is also required?
 
 
@aakansha yes, the questions of jee advanced will be only from that syllabus , but prepare those syllabus perfectly , they might be mix up 2-3 concepts at a time in a question , which req....
 
Umakant biswal 9 days ago
 
hello yes that is right for jee advace that syllabus is to prepare.all the best..................................................................................................
 
raj kumar 9 days ago
I am in class 12 and need books for IIT JEE preparation. How should I buy these books if in the below website, few important books cover different topics especially in math?...
 
 
Just buy Arihant books of calculus, algebra and coordinate geometry for Maths.It’s more than enough. Don’t run after the books otherwise, you will be confused at the end of the day which...
 
Amey one month ago
 
Im sorry, thats not what I meant. I was asking what all books would be required. For example, in math, SL Loney cevers Trigonometry and coordinate geometry, Hall&Knight covers higher...
 
James Chin one month ago
 
YOU CAN CLICK ON THE NAME OF THE BOOK YOU WANT TO BUY . JUST CLICK ON THE NAME OF BOOK. THEN CLICK ON THE OPTION buy now. you will be directed to the page. just fill the details . enjoy the ...
 
SAHIL one month ago
what are the top colleges in computerscience in india
 
 
Iiit Hyderabad cs is comparable to thise of iits with highest placement of 90 lpa
 
pranav 9 months ago
 
sum of top colleges in CS engenering in INDIA i had listed below
 
Gayatri Jayesh Bondriya 9 months ago
 
There is a long list for it, may it be the IITs or NITs and also the following ones may be considered – Jadavpur Uni, Kolkata,..........................Dharamsinh Desai Uni,...
 
Soneel Verma 9 months ago
LET a,b,c,d,e,f,g,h be distinct elements in set {-7,-5,-3,-2,2,4,6,13} . then the minimum possible value of {a+b+c+d} 2 + {e+f+g+h} 2 is........?
 
 
Dear rahul let a+b+c+d =x and e+f+g+h =y then x+y =8 so (x+y) 2 =x 2 +y 2 +2xy x 2 +y 2 = (x+y) 2 - 2xy =64- 2xy we know (x+y)/2 ≥ √xy xy ≤16 we can use this enequality when x...
 
Badiuddin askIITians.ismu Expert 6 years ago
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  • Complete JEE Main/Advanced Course and Test Series
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  • View Details
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USE CODE: FC20

  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: R 15,000
  • View Details

Get extra R 3,000 off
USE CODE: FC20

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