please tell about cut off of sc candidate in iit jee 2010 and accoding to 100 marks please give my sc and all india rank soon fast
                   

4 years ago

Share

Answers : (1)

                    

Hi ,
















































































SC Category



Rank


Aggregate Marks



1


326


101


170


201


146


301


132


401


121


501


112


601


105


701


99


801


95


901


91


967


89


ST Category



Rank


Aggregate Marks



1


319


101


114


201


91


208


89


Please feel free to post as many doubts on our disucssion forum as you can. If you find any question difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE preparation. All the best .

Regards,
Askiitians Expert
Amit - IT BHU

4 years ago

Post Your Answer

More Questions On IIT JEE Entrance Exam

Ask Experts

Have any Question? Ask Experts
Post Question
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!!
Click Here for details
Hi, I got around 6000 rank in JEE-ADV and around 13000 in JEE-Mains. I have got ISM-Dhanbad ECE and counselling of NITs (and BIT Mesra) are still going on. I want to be in CSE/IT branch. Can...
 
 
Corresponding to your ranks( Main & Advanced), the chances of you getting CSE in top 3 NITs are less. You have a pretty good chance of getting CSE BITS Mesra. ECE-ISM Dhanbad is a very...
  img
Aziz Alam 10 days ago
This question is regarding the interpretation of JEE Main results. I am confused on which Rank should i consider the possibilities of getting into NIT’s.. My All India Overall Rank is 9165,...
 
 
Overall Rank means your rank irrespective of category ( all students are given rank according to their score.GEN, SC,ST and others). Category Rank is the rank you got according to your marks...
  img
Aziz Alam 10 days ago
Which one is the best recommended book for physics for jee (main+advance)????????? D.C. pandey (5 volumes) by arihant publishers B.M. sharma (5 volumes) by CENGAGE Tata mcgraw hill (Complete...
 
 
1.Young & Freedman -University Physics 2.Resnick & Halliday These are kind of the books which stress on concepts as far as Physics is concerned.JEE is all about concepts. So I...
  img
Aziz Alam 5 days ago
 
You can directly use these books. These books will teach you from scratch. Thanks & regards Aziz Alam IIT Roorkee askIITians
  img
Aziz Alam 3 days ago
 
I am in 11 th,,, so i have just started preparing for jee.Can I directly use these for OR at first i have to solve some basic books????? @ AZIZ ALAM SIR
 
Sankalp Tiwari 4 days ago
sir , i got jeemain2014 287marks, bitsat-2014 336 marks , and jeeadvance2014 219marks. i am interest CSE IN HYDERABAD only , which engineering college is better for future opportunities and...
 
 
Hi, You can predict your rank in JEE Mains and Advanced with the help of the following provided links. Compare your rank with previous year cut-off of various institutes. This will give you...
  img
Apoorva Arora one month ago
 
You have a very good chances of getting CSE at IIIT Hyderabad. I think you should go there because you would get good package & research opportunity there. Good Luck! Thanks &...
  img
Jitender Singh one month ago
hello Sir, I am a B.Tech student from cse steam and I have selected in a good multinational company and I am willing to write GATE 2010.Most of my friends suggested me to opt for the job as...
 
 
If you are from IIT then there is not write any gate exam and M Tech will not be a good choice. because after M Tech fron any IIT , the salary difference will be 5 to 8K@month only. and that...
 
AskiitianExpert Pramod-IIT-R 4 years ago
If tan A = 2/3 find the value of (3sin A + 4 cos A)/ (3sin A – 4 cosA) (A) - 3 (B) - 4 (C) - 5 (D) none of these 8. sin2 1 + sin2 3 + sin2 5 + sin2 7 + ……… + sin2 89 =
 
 
Sin2 1 + sin2 3 + ... + sin2 45 + ... + sin2 87 + sin2 89 = sin2 1 + sin2 3 + ... + 1/2 + ... + sin2 (90-3) + sin2 (90-1) = sin2 1 + sin2 3 + ... + 1/2 + ... + cos2 87 + cos2 89 Grouping the...
 
Karthik J 6 months ago
 
(A) -3 (3sin A + 4 cos A)/ (3sin A – 4 cosA) Divide Numerator and Denominator by cos A to get: (3tan A + 4 )/ (3tan A – 4) Substitute the value of tan A to get the final answer as -3..
 
Karthik J 6 months ago
 
rationalise them and take 16 cos(square)A common from numerator and denominator and cancel out. now put the value of tanA
 
sheshmani sharma 6 months ago
View all Questions »