MY CART (5)

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price:

There are no items in this cart.
Continue Shopping
                   Sir,

Kindly send me the cutoff for IITJEE-2009 rank wise and branchwise.

5 years ago

Share

Answers : (1)

                                        

Dear richa


For further details you can visit the following:

http://www.askiitians.com/IIT-JEE-2010-Cut-Offs.aspx

http://www.askiitians.com/iits-2009-2010-opening-and-closing-rank.aspx



for cutoff in new IITs  check the link


http://jee.iitd.ac.in/openclose09.htm    (this link includes the more detail analysis)


for code of the cources check the councelling broucher 2009.

Please feel free to post as many doubts on our discussion forum as you can.
If you find any question Difficult to understand - post it here and we will get you
the answer and detailed  solution very  quickly.

 We are all IITians and here to help you in your IIT JEE preparation.

All the best.
 
Regards,
Askiitians Experts
Badiuddin

5 years ago

Post Your Answer

More Questions On IIT JEE Entrance Exam

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!!
Click Here for details
I am a foreign citizenship holder.(Tanzanian). Is there a foreigner’s quota for admissions in IIT ? Which IITs give such quota and in which fields ? How much rank is good enough to get...
 
 
Yes of course, there is NRI reservation scheme in IIT-JEE. Please check the prospectus once, You will get whole info.. Good...
  img
Saurabh Kumar 6 months ago
 
@saurabh kumar can u please give the link of the prospectus ? i cant find it oline ? thanks ! -ayush.
 
Ayush Mehta 5 months ago
 
@saurabh kumar can u please give the link of the prospectus ? i cant find it oline ? thanks ! -ayush.
 
Ayush Mehta 5 months ago
F(x)= (2e^x-7)/(7e^x+6) f^-1(x)=?
 
 
f(x) = (2e^x - 7)/(7e^x + 6) f(x) = {2(e^x - 7/2)}/{7(e^x + 6/7)} f(x) = (2/7)(e^x - 7/2)/(e^x + 6/7) Let x = f^-1(x) f(f^-1(x)) = (2/7)(e^f^-1(x) - 7/2)/(e^f-1(x) + 6/7) The left side...
 
vikas yadav one month ago
 
7x/2 = (e^f^-1(x) + 6/7 - 6/7 - 7/2)/(e^f^-1(x) + 6/7) 7x/2 = 1 - (6/7 + 7/2)/(e^f^-1(x) + 6/7) Multiply by 2: 7x = 2 - (12/7 + 7)/(e^f^-1(x) + 6/7) Multiply numerator and denominator by...
 
vikas yadav one month ago
Do you believe in Angles?
 
 
yes i agree in angles.
 
d.kojalrani one month ago
 
anglee????????????
 
vikas yadav one month ago
What is OSI Reference Model ??
 
 
The Open System Interconnection reference model was created by the International Organizaiton for Standardization (ISO) to provide a model that network vendors could follow when developing...
  img
Deepak Patra 6 years ago
parabola part 1 doubts
 
 
Please complete the question. ........................................................................................................................................ Assuming with this much...
  img
Ravi 6 months ago
 
Please type the complete question as to what do we have to do in the question or what has been asked in the question?...
  img
Ravi 6 months ago
 
sir,i have attached 4 different pages for parabola doubts,so it would be better if you go through all the four attachments,one half of this question is there on the attached file named...
 
vineet chatterjee 6 months ago
Any additional help or tip for bitsat ?
 
 
* If you have enough time for the exam, pick a chapter you are weak in and one that is important from the exam standpoint. * Or if you do not have enough time, pick a chapter that you are...
 
Drake 27 days ago
 
Well yes they are more than enough . U have to also prepare for english too .
 
Drake 27 days ago
 
Thanks for the ans Mr Drake . Will ncert work for it ?
 
Rahul 27 days ago
View all Questions »