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question no 25 in jee 2010 paper I some have given the answerr as 4 and some have given as 3 . can you please explain 


The number of neutorons emitted when 235/92 U undergoes controlled nuclear fission to 142/54 Xe and 90/38 Sr is 

4 years ago

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Answers : (1)

                                        

Dear Veluri


Its a simple and straight forward question


clearly the emmited electron is 3


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Badiuddin

4 years ago

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