question no 25 in jee 2010 paper I some have given the answerr as 4 and some have given as 3 . can you please explain 

The number of neutorons emitted when 235/92 U undergoes controlled nuclear fission to 142/54 Xe and 90/38 Sr is 

4 years ago


Answers : (1)


Dear Veluri

Its a simple and straight forward question

clearly the emmited electron is 3

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4 years ago

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