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Hi VAIBHAV,
USE THIS CONCEPT,
relative velocity of separartion = e*relative velocity of approach
AS THE BALLS ARE EQUAL AND ARE UNDERGOING HEAD ON COLLISION
The speed of the balls will be same after collision
relative velocity of approach is 6-(-6)=12m/s., coefficient of restitution is 1/3
put this in the above equation,
you will get relative velocity of separation=4m/s
as the balls will move in opposite direction after collision, the velocity of one ball will be 2m/s and -2m/s for other. (i.e relative velocity=2-(-2)=4m/s)
hence speed of each ball will be 2m/s (considering inly magnitude of the velocities)
Plz approve if you are satisfied :)
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