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Now we know that abs(a)+abs(b)=16abs(a)+abs(b)=16
And since this is a vector triangle, using Pythagoras theorem. a2−b2=64a2−b2=64
From abs(a)+abs(b)=16abs(a)+abs(b)=16
Make abs(b)abs(b) the subject followed by squaring the equation
This will give you
b2=256−32abs(a)+a2b2=256−32abs(a)+a2
(abs(x) squared= x^2 due to commutative law of vector scalar multiplication)
Substitute into the Pythagoras theorem equation and you will get
32abs(a)=32032abs(a)=320
abs(a)=10abs(a)=10
And from there substitute back into equation to get abs(b)=6
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