the position vector of particle changes from 10 m east to 20 m north in one second with respect to a fixed point .the magnitude of average velocity of a particle is A =10root5 metre per second

Question

Harshit · Answer

Velocity=change in position with respect to timeChange in position =10icap-20jcap and angle between them=90° Magnitude = [(10)^2+(20)^2 - 2*10*20*Cos(90)°]^1/2= 10 root 2Average velocity=10root2/1= 10root2

Thank you for registering.

Register Now and Win Upto 25% Scholorship for a Full Academic Year !

Enter Your Details

Registration done!

Guest

the position vector of particle changes from 10 m east to 20 m north in one second with respect to a fixed point .the magnitude of average velocity of a particle is A =10root5 metre per second

the position vector of particle changes from 10 m east to 20 m north in one second with respect to a fixed point .the magnitude of average velocity of a particle is
A =10root5 metre per second

1 Answers

Think You Can Provide A Better Answer ?

Other Related Questions on General Physics

ASK QUESTION

Answer and earn gift vouchers

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Complete Self Study Package designed by Industry Leading Experts

Live 1-1 coding classes to unleash the Creator in your Child

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Register Now & Win Upto 25% Scholorship

Thank you for registering.

Register Now and Win Upto 25% Scholorship for a Full Academic Year !

Enter Your Details

Registration done!

Guest

IIT JEE Courses

One Year IIT Programme

Two Year IIT Programme

Crash Course

NEET Courses

One Year NEET Programme

Two Year NEET Programme

One to One

School Board

Live Online classes

Class 11 & 12

Class 9 & 10

Class 6, 7 & 8

Test Series

JEE test series

NEET test series

C.B.S.E test series

Complete Self Study Packages

FULL COURSE

For class 12th

For class 11th

the position vector of particle changes from 10 m east to 20 m north in one second with respect to a fixed point .the magnitude of average velocity of a particle is A =10root5 metre per second

the position vector of particle changes from 10 m east to 20 m north in one second with respect to a fixed point .the magnitude of average velocity of a particle is A =10root5 metre per second

1 Answers

Think You Can Provide A Better Answer ?

Other Related Questions on General Physics

ASK QUESTION

Answer and earn gift vouchers

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Complete Self Study Package designed by Industry Leading Experts

Live 1-1 coding classes to unleash the Creator in your Child

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Register Now & Win Upto 25% Scholorship

the position vector of particle changes from 10 m east to 20 m north in one second with respect to a fixed point .the magnitude of average velocity of a particle is
A =10root5 metre per second