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P=b-x^2/at Find the dimension of a and b wherexis the distance and p is the power t is time

P=b-x^2/at Find the dimension of a and b wherexis the distance and p is the power t is time

Grade:11

3 Answers

Vikas TU
14149 Points
6 years ago
Dear Student,

Given information 
P = b-x^2/at 
x = separate =[L] 
as the govern of documentation 
measurement of b will be equivalent to measurement of [x^2] 
Measurement of b = [L2] 
P.at = b-x^2 
As the measurement of Power is [ML2T-3] 
Put in the condition 
[ML2T-3] [a][T] = [L2] 
[a] = [M-1 T2] .
 
Cheers!!
Regards,
Vikas (B. Tech. 4th year
Thapar University)
Vatsal
15 Points
4 years ago
P=b-x^2/at
x=L
x^2=L^2
b-x^2=0
b=x^2
b=L^2
P=b-x^2/at
P at=x^2
M^1L^2T^-3 .a. T=L^2
M^1L^2T^-2. a=L^2
a=L^2/M^1L^2T^-2
a=M^-1T^2
Ajeet Tiwari
askIITians Faculty 86 Points
3 years ago
hello student

642-243_measurnment fi.png

Hope it helps
Thankyou

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