if total energy of electron in nth orbit is X ,its KE & PE in the same orbit respectively are
a)X,-2X
b)2X,-3X
c)X/2,-3X/2
d)-X,2X
only option d is in accordance to the question but how can KE be negative,please let me know if the question is incorrect or there is any other way to solve this.

Question

Abhishek Singh · Answer

It is because the total energy of electron is -ve total energy=1/2P.E=-K.e

Shubham J · Answer

T.E is negative then X should be a negative number,therefore 2x=PE should also be a negative no., and -X should be a positive number.Hence KE is positive.Thank u Abhishek u gave me some idea..

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if total energy of electron in nth orbit is X ,its KE & PE in the same orbit respectively are a)X,-2X b)2X,-3X c)X/2,-3X/2 d)-X,2X only option d is in accordance to the question but how can KE be negative,please let me know if the question is incorrect or there is any other way to solve this.

if total energy of electron in nth orbit is X ,its KE & PE in the same orbit respectively are
a)X,-2X
b)2X,-3X
c)X/2,-3X/2
d)-X,2X
only option d is in accordance to the question but how can KE be negative,please let me know if the question is incorrect or there is any other way to solve this.

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if total energy of electron in nth orbit is X ,its KE & PE in the same orbit respectively are a)X,-2X b)2X,-3X c)X/2,-3X/2 d)-X,2X only option d is in accordance to the question but how can KE be negative,please let me know if the question is incorrect or there is any other way to solve this.

if total energy of electron in nth orbit is X ,its KE & PE in the same orbit respectively area)X,-2Xb)2X,-3Xc)X/2,-3X/2d)-X,2Xonly option d is in accordance to the question but how can KE be negative,please let me know if the question is incorrect or there is any other way to solve this.

2 Answers

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if total energy of electron in nth orbit is X ,its KE & PE in the same orbit respectively are
a)X,-2X
b)2X,-3X
c)X/2,-3X/2
d)-X,2X
only option d is in accordance to the question but how can KE be negative,please let me know if the question is incorrect or there is any other way to solve this.