find the dimension of a and b in equaton: F=ax+bt^2,where F is force,x is distance & t is time

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Gaurav Jain · Answer

According to principle of homogeneity [F]=[ax]=[bt²] Taking [MLT-²]=[aL] [a]=[MT-²] Similarily [bT²]=[MLT-²] [b]=[MLT-⁴]

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find the dimension of a and b in equaton: F=ax+bt^2,where F is force,x is distance & t is time

find the dimension of a and b in equaton: F=ax+bt^2,where F is force,x is distance & t is time

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find the dimension of a and b in equaton: F=ax+bt^2,where F is force,x is distance & t is time

find the dimension of a and b in equaton: F=ax+bt^2,where F is force,x is distance & t is time

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