0

Guest

Courses New

Find the angular displacement of a particle in 6 sec on a circle with a angular velocity 2π/3

Find the angular displacement of a particle in 6 sec on a circle with a angular velocity 2π/3

Grade:12

2 Answers

Vikas TU
14149 Points
7 years ago
Angular displacement of a particle in 6 sec on a circle with a angular velocity 2π/3 is:
thetha = w*t = > 2pi*6/3 = > 4pi rad.
Ashmak Moon
27 Points
7 years ago
There is a difference between angular distance and angular displacement, angular displacement is a vector quantity with magnitude equal to the shortest distance between initial and final positions of a particle and the direction is from initial to final position. in our case, the distance moved is complete two circomference '4pi’ and hence displacement is a null vector (a vector with zero magnitude and undetermined (not necessarily) direction. In our example, the direction is same as the direction of the angular velocity,i.e., clockwise or anticlockwise. 

Think You Can Provide A Better Answer ?

Other Related Questions on General Physics

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More