at an instant car A Is moving with constant velocity of 30 m/s and a stationary car B with acc. 2 m/s^2 in same direction and location, the time after which they cross each other

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Vikas TU · Answer

Let car A covered the distance as 'x’ meters then, x = 30*t.................(1) For car B, x = 0 + 0.5*2*t^2...............(2) solving both the eqns. we get, t^2 = 30t t (t – 30 ) = 0 t = 30 seconds.

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at an instant car A Is moving with constant velocity of 30 m/s and a stationary car B with acc. 2 m/s^2 in same direction and location, the time after which they cross each other

at an instant car A Is moving with constant velocity of 30 m/s and a stationary car B with acc. 2 m/s^2 in same direction and location, the time after which they cross each other

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at an instant car A Is moving with constant velocity of 30 m/s and a stationary car B with acc. 2 m/s^2 in same direction and location, the time after which they cross each other

at an instant car A Is moving with constant velocity of 30 m/s and a stationary car B with acc. 2 m/s^2 in same direction and location, the time after which they cross each other

1 Answers

Think You Can Provide A Better Answer ?

Other Related Questions on General Physics

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