A super bowl is to bounce elastically back and forth between two rigid walls at a distance D from each other neglecting gravity and assuming the velocity of Super Bowl to be we not horizontally the average force being exerted by the superbowl on each wall is

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Sanjana · Answer

As the ball do back and forth motion,the distance covered by the ball is 2dSo time taken=2d/v∆p=2mvAs F∆t=∆pF=2mv/2d/vAs v go upper side and become v^2and 2 from both upper and lower side get cancelled out and we get-F=mv^2/d

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A super bowl is to bounce elastically back and forth between two rigid walls at a distance D from each other neglecting gravity and assuming the velocity of Super Bowl to be we not horizontally the average force being exerted by the superbowl on each wall is

A super bowl is to bounce elastically back and forth between two rigid walls at a distance D from each other neglecting gravity and assuming the velocity of Super Bowl to be we not horizontally the average force being exerted by the superbowl on each wall is

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A super bowl is to bounce elastically back and forth between two rigid walls at a distance D from each other neglecting gravity and assuming the velocity of Super Bowl to be we not horizontally the average force being exerted by the superbowl on each wall is

A super bowl is to bounce elastically back and forth between two rigid walls at a distance D from each other neglecting gravity and assuming the velocity of Super Bowl to be we not horizontally the average force being exerted by the superbowl on each wall is

1 Answers

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Other Related Questions on General Physics

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