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A particle is thrown with a speed of 20 m/s at an angle of 30 above horizontal from the top of a tower 15 m high. Time after which velocity becomes perpendicular to initial velocity is : (g = 10 m/s2) (A) 4 s (B) 1 s (C) 3 s (D) None of these

 A particle is thrown with a speed of 20 m/s at an angle of 30 above horizontal from the top of a
tower 15 m high. Time after which velocity becomes perpendicular to initial velocity is : (g = 10 m/s2)
(A) 4 s (B) 1 s (C) 3 s (D) None of these

Grade:11

1 Answers

PASUPULETI GURU MAHESH
126 Points
7 years ago
From given data based we find out time only that is not need to total time taken that’s mean time of flight.  So we just calculate only time taken body then T= u sin teeta/g
            T= (20×1/2)/10
              =1sec the velocity is perpendicular to the initial velocity.
 
   Thank you
 
then 1 sec after

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