a particle is thrown vertically upwards with velocity such that time of flight is more than 2 sec. Prove that in the last second of its upward journey it will travel a distance 5m.

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Vikas TU · Answer

T = 2 = 2u/g => u = 9.8 m/s (minimum velocity) in last second .i.e T -1 = 2-1 = 1 second, h1 = 9.8*2 -0.5*g*4 h2 = 9.8*1 – 0.5*g*1 Answer is h2 – h1 rest u can do!

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a particle is thrown vertically upwards with velocity such that time of flight is more than 2 sec. Prove that in the last second of its upward journey it will travel a distance 5m.

a particle is thrown vertically upwards with velocity such that time of flight is more than 2 sec. Prove that in the last second of its upward journey it will travel a distance 5m.

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a particle is thrown vertically upwards with velocity such that time of flight is more than 2 sec. Prove that in the last second of its upward journey it will travel a distance 5m.

a particle is thrown vertically upwards with velocity such that time of flight is more than 2 sec. Prove that in the last second of its upward journey it will travel a distance 5m.

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