A. Particle is projected from ground at an angle 60°with horizontal with a speed of 10√3 m/s from point A.At the same time the sufficient long wedge is made to move with constant velocity of 10√3m/s towards right.The time in second after which particle will hit the wedge will be

Question

Vikas TU · Answer

Dear Student,
The particles range = The distance travelled by the wedge in the same time for them to hit each other
=> u²sin2q/g = dxt
=>300 x 2x sin 60 x cos60/10 = 10 t
=>t=1.5s.

Cheers!!

Regards,

Vikas (B. Tech. 4^th year
Thapar University)

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A. Particle is projected from ground at an angle 60°with horizontal with a speed of 10√3 m/s from point A.At the same time the sufficient long wedge is made to move with constant velocity of 10√3m/s towards right.The time in second after which particle will hit the wedge will be

A. Particle is projected from ground at an angle 60°with horizontal with a speed of 10√3 m/s from point A.At the same time the sufficient long wedge is made to move with constant velocity of 10√3m/s towards right.The time in second after which particle will hit the wedge will be

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A. Particle is projected from ground at an angle 60°with horizontal with a speed of 10√3 m/s from point A.At the same time the sufficient long wedge is made to move with constant velocity of 10√3m/s towards right.The time in second after which particle will hit the wedge will be

A. Particle is projected from ground at an angle 60°with horizontal with a speed of 10√3 m/s from point A.At the same time the sufficient long wedge is made to move with constant velocity of 10√3m/s towards right.The time in second after which particle will hit the wedge will be

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