0

Guest

Courses New

A particle is aimed at a mark on the horizontal plane through the point of projection. It falls 12 meters short when the angle of projection is 15 degrees while it overshoots the mark by 24 meters when the angle is 45 degrees. Find the angle of projection to hit the mark.

A particle is aimed at a mark on the horizontal plane through the point of projection. It falls 12 meters short when the angle of projection is 15 degrees while it overshoots the mark by 24 meters when the angle is 45 degrees. Find the angle of projection to hit the mark.

Grade:12th pass

1 Answers

Arun
25750 Points
6 years ago
R’ is the required range = [u²/g] sin 2θ 
When θ = 15° 
R(15) = [u²/g] sin 30 = R’ – 12 where R’ is the required range .-----1 
When θ = 45° 
R(45) = [u²/g] sin 45 = R’ + 24 where R’ is the required range ---2. 

2-1gives 0.207[u²/g] = 36 
[u²/g] = 173.9130 

Substituting in 1 
[u²/g] sin 30 = R’ – 12 

173.9130* sin 30 = 173.9130 sin 2θ - 12 
sin 2θ = 0.569 
θ = 17.34° or 72.76° 

For these two angles the projectile will reach the mark. 

Think You Can Provide A Better Answer ?

Other Related Questions on General Physics

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More